"6.3072 g" >>"Molarity" = "Moles of solute"/"Volume of solution (in litres)" "0.45 M" = "n"/"0.4 L" "n = 0.45 M × 0.4 L = 0.18 mol" You need "0.18 mol" of "NH"_4"OH" Molar mass of "NH"_4"OH" …

Aug 29, 2016 · So this is a propanol derivative: "2-methylpropan-2-ol" For "isopropyl alcohol", H_3C-CH (OH)CH_3, the longest chain is again three carbons long, and C2 is substituted by …

Nov 26, 2017 · HCOO^(-)(aq) + H_2O(l) rightleftharpoons HCOOH(aq) + OH^(-)(aq) If the solution is diluted, the reaction will shift left, because (i) water isn't in the equilibrium expression, and …

How about these? > (a) With "HCN" The "HCN" adds across the α "C=O" group to form a cyanohydrin. underbrace ("CH"_3"COCOOH")_color (red) ("pyruvic acid") + "HCN" → ...

Dec 23, 2017 · These are ostensibly acid-base reactions.... For ammonium we could write.... NH_4^+ +HO^(-) rarr NH_3(aq) + H_2O(l) For methanol, the acid base reaction would proceed ...

Here, let's balance the nitrogens first. There are two on the left due to the presence of ammonium sulfate, but only one on the right because of one ammonia molecule, so we multiply ammonia …

The sodium ions remain in solution as spectator ions. If XS sodium hydroxide is added the precipitate redissolves to give the soluble plumbate (II) ion. A simple way of writing this is: …

The correct answer is a) hydroxide, carbonate, and hydrogen carbonate. Alkalinity is another word for basicity (the concentration of hydroxide ions). a) Hydroxide ions OH⁻ are the strongest …

calculate moles of Acid, calculate moles of Base. subtract, #OH^-# should be in excess, calculate Molarity of #OH^-# , pOH = -log (#OH^-#), then 14-pOH = pH

OH^- OH^- is the more reactive ion. KOH is quite completely dissociated and if OH^- is in a great concentration it can react with metals and with inorganic and organic compounds.